2/[sqrt(5)]
show if you can.
2007-06-25 04:29:31 · 5 answers · asked by lushay 2 in Science & Mathematics ➔ Mathematics
The idea is to get rid of the sqrt(5) in the denominator. You do this by multiplying and dividing by sqrt(5). So
2/sqrt(5) = (2/sqrt(5)) * (sqrt(5)/sqrt(5)) = 2*sqrt(5)/5
Math Rule!
2007-06-25 04:34:45 · answer #1 · answered by Math Chick 4 · 0⤊ 1⤋
Rationalization (in algebra) consists in removing roots from the denominators.
In this case, you multiply and divide by sqrt(5) (this is the equivalent of multiplying by 1):
2/sqrt(5) x sqrt(5)/sqrt(5) = 2sqrt(5)/ (sqrt(5))^2 = 2sqrt(5)/5
2007-06-25 11:35:59 · answer #2 · answered by Israfel 3 · 0⤊ 0⤋
2 / â5 = 2.â5 / 5 = (2/5).â5
2007-06-29 04:53:23 · answer #3 · answered by Como 7 · 0⤊ 1⤋
multipy the square root of 5 by the top and bottom
2/sqrt(5) x sqrt(5)/sqrt(5)
2007-06-25 11:33:02 · answer #4 · answered by soulsearching 2 · 0⤊ 1⤋
Mult top and bottom by the sq rt of 5
2sq rt (5)/sq rt(25)
=2 sq rt (5)/5
2007-06-25 11:33:37 · answer #5 · answered by ania 2 · 0⤊ 1⤋