how do you answer this problem?

Question

The length of a rectangular frame is 8 cm more than the width. The perimeter of the frame is 44 cm. Find the width of the frame.

Answer 1

Two equations:

L = W + 8 ("length 8 more than width")
P = 2L + 2W (perimeter of a rectangle)

Substitute the first into the second, using the given value for perimeter as well:

P = 2L + 2W
44 = 2(W + 8) + 2W
44 = 2W + 16 + 2W
28 = 4W
W = 7 cm

Now you can go back and solve for L:

L = W + 8
L = 7 + 8
L = 15 cm

Knowing that W=7 and L=15, check with the perimeter equation to verify the solution:

P =? 2L + 2W
44 =? 2*15 + 2*7
44 =? 30 + 14
44 = 44

Even though you were only asked for the width, it's not a bad idea to complete the problem (calculate the length as well), and then check the result. It will help you catch any mistakes you might have made.

Answer 2

Let the width of the frame be w cm
Hence the length of the frame is w+8 cm
Therefore
2(w+w+8)=44
or,2w+8=44/2=22
or,2w=22-8=14
or,w=14/2=7
The width of the frame is 7 cm

Answer 3

width = 7 cm
length = 15 cm

Answer 4

The perimeter is 2L + 2W, that's first.

Second you need to know what L and W are.

W = X
L = X+8

So...
2X + 2(X + 8) = 44
4X +16 = 44
4X = 28
X = 7

Width of frame is 7, length is 15

Answer 5

ok first draw the rectangle. 2 sides are labeled x and the others are x+8.
then add all four sides together and you get 4x+16=44.
Then you subtract 16 from both sides.
4x=28.
divide both sides by 4.
x=7

Answer 6

let
L = length
W = width

2L + 2W = 44
L=W+8

put the second equation into the first:
2*(W+8) + 2W =44
2w +16 +2W =44
4W = 28
W=7
L=W+8=7+8=15

W=7
L=15

Answer 7

44=2x+2x+16
28=4x
x=7
W=7cm.