how do you solve this?

Question

A banner in the shape of an isosceles triangle has a base that is 5 inches shorter than either of the equal sides. If the perimeter of the banner is 37 inches, then what is the length of the equal sides?

Answer 1

let the lengths of the equal sides be x inches.So the base is x-5 inches
Therefore,
x+x+x-5=37
or,3x-5=37
or,3x=37+5=42
or,x=42/3=14
Therefore the lengths of the equal sides ae 14 inches each

Answer 2

You know that there are 2 sides equal and one side that is 5 less than those other two sides. This leads to the equation:

2x + (x-5) = 37
where x is the distance of the longer triangle sides.

This gives the result that x = 42/3 or 14.

The length of the equal sides is 14.

Answer 3

Equal sides = 14 inches
Base = 9 inches

Answer 4

Let equal sides be x inches.
Other side = x - 5 inches.
x + x + x - 5 = 37
3x - 5 = 37
3x = 42
x = 14
Length of equal sides is 14 inches.

Answer 5

ok...lets see...let ABC be dat isoceless triangle with AB=AC

now we hav dat third side dat is the base is 5 inches less than AB and AC which are equal that is let AB=AC=x
den base side BC=x-5 inches
perimetr of ABC= AB+BC+CA
therfore 37=x+x+x-5
37=3x-5
42=3x
x=14

Answer 6

(37 - 5) / 2 = 16cm for each of the equal sides.

Answer 7

Very easy question.. If you can't answer this, how can you pass the class?