Find the distance traveled in 15 seconds by an object moving with velocity of v(t) = 20 + 7 cos t feet per second.
2007-06-25 01:13:10 · 4 answers · asked by x_abbie_2006_x 1 in Science & Mathematics ➔ Mathematics
Integrate and use the inital condition to solve for C, then just plug in 15 sec
300 + 7sin(15) + C
2007-06-25 01:18:30 · answer #1 · answered by Jared D 2 · 0⤊ 1⤋
s= integral of v(t)dt=integral of (20+7cost)dt=20t+7sint+C
when t=0,s=0
0=C
so s=20t+7sint
when t=15,s=300+7sin15=300+7x0.26=301.81ft
2007-06-25 01:37:19 · answer #2 · answered by Anonymous · 0⤊ 1⤋
I agree with the former answer but in Calculus you should use real variable for t so t should be expressed in radians and
sin15 =0.65
2007-06-25 02:06:04 · answer #3 · answered by santmann2002 7 · 0⤊ 1⤋
stick to your formula's. you'll get it. keep trying to work this out by yourself. you'll get more out of it and learn faster when you have another problem like it.
2007-06-25 01:18:15 · answer #4 · answered by cam-the-man 2 · 0⤊ 2⤋