anyone?.........?

Question

Given A = {1, 4, 7, 10} and B = {2, 5, 8, 11}, find n (A x B)

plz show work & all steps thanks

Answer 1

Reading A x B as A times B, this seems to indicate that you multiply every element in set A by every element in set B, which would give
2, 5, 8, 11
8, 20, 32, 44
14, 35, 56, 77
20, 50, 80, 110
Counting these yields n(A x B) = 16

Answer 2

In order to multiply the two matrix together the B matrix should be vertical and not horizontal or vise versa with A being vertical and B being horizontal. If that is the case you would multiply it like so

| 1 |
| 4 | *(2 5 8 11) =
| 7 |
|10|

= (1*2)+(4*5)+(7*8)+(10+11)
= 2+20+56+110
= 188

You will get the same answer if a is horizontal and b is vertical. As you can see you get the answer by multipling the corresponding row(1rst, 2nd, etc) * the corresponding column (1st, 2nd, etc)

Answer 3

its simple
n(A)=4 and n(B)=4
therefore the n(AxB)=n(A)xn(B)
i.e.4x4 that gives 16
16 because when every no. of set A is made an ordered pair with set B the no of ordered pair is 16 thats ur answer

Answer 4

The number of elements in a Cartesian product, n(A x B), is the number of elements in set A, n(A), multiplied by the number of elements in set B, n(B):

Answer 5

is this a matrix problem, if so then its impossible...