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An experiment is conducted where two standard 6 sided dice are rolled and the sum of the numbers that show face up is recorded.

A. What values can the random variable assume?
B. List the probability distribution of the random variable?

Can someone help me answer this question pleasee..

2007-06-24 19:58:49 · 3 answers · asked by freaking_naj 1 in Science & Mathematics Mathematics

3 answers

Each die can display the numbers 1 through 6 with equal probability (in theory) so the values and relative probabilities are:
1 + 1 = 2
1 + 2 = 3
2 + 1 = 3
1 + 3 = 4
2 + 2 = 4
3 + 1 = 4
and so forth for a total of 36 possibilities:
2 , 1/36
3 , 2/36 = 1/18
4 , 3/36 = 1/12
5 , 4/36 = 1/9
6 , 5/36
7 , 6/36 = 1/6
8 , 5/36
9 , 4/36 = 1/9
10 , 3/36 = 1/12
11 , 2/36 = 1/18
12 , 1/36

2007-06-24 20:23:11 · answer #1 · answered by Helmut 7 · 0 0

Here is the correct answer:
The random variable can take values of 2-12.

The probability distribution is:
2 and 12 w/prob 1/36 each
3 and 11 w/prob 2/36 each
4 and 10 w/prob 3/36 each
5 and 11 w/prob 4/36 each
6 and 8 w/prob 5/36 each
7 w/prob 6/36

you can reduce those probabilities if you like

2007-06-24 21:12:29 · answer #2 · answered by Anonymous · 0 0

Random variables takes values from 1-6.prob. of each of them is one sixth.then you can find CDF and its derivative pdf using above facts.read books!!!!

2007-06-24 20:08:53 · answer #3 · answered by Anonymous · 0 0

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