Find the solutions... 64x^2-49=0?

Answer 1

factor
(8x-7)(8x+7)=0
set both equal to zero
8x-7=0 and 8x+7=0
8x=7 8x=-7
x=7/8 x= -7/8

Answer 2

Answer for your Quadratic Equation



Your Problem is 64 x2 +0 x -49 = 0
We can solve this problem by the following methods
Note : the multiplication sign is * here to avoid confusion with x

By Using Factorization Method :
64 x2 +0 x -49 = 0
64 ( x2 -0.875 x +0.875 x -49 ) = 0
64 (( x2 -0.875 x ) + ( 0.875 x -49 )) = 0
64 ( x -0.875 ) ( x +0.875 ) = 0, divide both side with 64
( x -0.875 ) ( x +0.875 ) = 0, which is true if
( x -0.875 ) = 0 OR ( x +0.875 ) = 0, so we got these answers
x = 0.875 OR x = -0.875

By Using ABC Formula :
64 x2 +0 x -49 = 0
We have to turn it into ax2 +b x + c = 0 form, so
a=64 , b=0 , c=-49
Use the following formula :
x = (-b+(b2-4ac)(1/2))/2a OR x = (-b-(b2-4ac)(1/2))/2a, enter the value of a,b,c to this formula
x = (0+( (0)2 - 4 * 64 * -49)(1/2))/(2 * 64) OR x = (0-( (0)2 - 4 * 64 * -49)(1/2))/(2 * 64)
x = (0+(12544)(1/2))/(2 * 64) OR x = (0-(12544)(1/2))/(2 * 64)
x = (0+(12544)(1/2))/128 OR x = (0-(12544)(1/2))/128
x = (0+112)/128 OR x = (0-112)/128
x = 0.875 OR x = -0.875

Answer 3

64x^2 - 49 = 0
(8x - 7)(8x+7) = 0
x = 7/8, -7/8

Answer 4

64x^2-49=0

64x^2=49

x^2=49/64

x=(49/64)^1/2

x= ±7/8

Answer 5

64 x^2 IS NOTHING but (8x)^2
and, 49 = 7^2

so, 64x^2-49=0
= (8x)^2 - 7^2
= (8x-7)(8x+7) as a^2-b^2 =(a-b)(a+b)
now, (8x-7)(8x+7) = 0
now, 8x-7=0 or 8x+7=0
so, x= 7/8 or x= -7/8

Answer 6

64x^2 - 49 = 0
8x - 7 = 0
8x = 7
x = 7/8

Answer 7

add 49 to both sides:

64x^2=49

then square root both sides:

8x=(+/-)7

Divide both sides by 8:

x= (+/-) 7/8

Answer 8

(8x - 7).(8x + 7) = 0
x = 7/8 , x = - 7/8