Another Buoyancy and Weight Problem?

Question

As steel cube 0.30 m on each side is suspended from a scale (that measure's weight in Newtons) and completely immersed in water. What will the scale read?

Note: the density of steel 7800 kg/m^3

Answer 1

The scale will read an amount equal to the volume of the cube times the difference between steel density and water density.
which is 10^3 kg/m^3

0.3^3 * (7800 - 1000)*g = 183.6*g newtons = 1,801 newtons

However, if it is an ordinary scale, the reading will actually be 183.6kg. The scale measures newtons, but reports the value as kg in a gravity field of 1g. It should really read kgwt, but that is not used much. Therefore, an amount of matter with mass of 1kg will read 1kg on the scale, even though the weight is 1*g newton.