Please explain how to do this:
Name the smallest counting number by which to multiply the first number so that the product is a multiple of the second number.
Example: 2 x 3 x 5; 2 x 3 (squared) x 7
Solution: What factors of the second number are not factors of the first number? 3 and 7. Therefore, 3 x 7, or 21.
2007-06-24 12:29:58 · 4 answers · asked by babilv 2 in Science & Mathematics ➔ Mathematics
Thanks, not looking for LCM though.
2007-06-24 12:47:35 · update #1
The first number is 30. The second is 126.
Of the second number, the factors 2 and a 3 are found in the first. The second 3 and 7 are not. So if you multiply the first number by 3 and 7 (21), you will get a number that is a multiple of 126.
30 * 21 = 630.
630 = 126 * 5
2007-06-24 12:57:25 · answer #1 · answered by TychaBrahe 7 · 0⤊ 1⤋
Sounds like you're looking for the lowest common multiple of two numbers.
So if the first number has prime factors a, b, and c,
and the second number has prime factors a, b, d, and e,
then the lowest common multiple will be a*b*c*d*e - that is, just multiply together all of the different factors.
Hope this helps?
.
2007-06-24 19:42:49 · answer #2 · answered by tsr21 6 · 0⤊ 1⤋
2x3=6
6 squared is 36
36x7=252
2x3x5x252=7,560
3.8785218 is the smallest counting number.
lol.. I really don't have a clue...
2007-06-24 19:52:12 · answer #3 · answered by shoVel 3 · 0⤊ 0⤋
i did not understand a single word of that question......
2007-06-24 19:38:46 · answer #4 · answered by Yogaflame 6 · 0⤊ 0⤋