Probablities!!! HELP!?

Question

2.) find probablity for the experiment of tossing a six- sided die twice.
-the sum is at least 7.
answer i got was 7/36 & im not sure of this tho.

2.) One hundred college students were interviewed to determine their political party affiliations and whether they favored a balanced- budget amendment to the constitution.

23 democrats & 32 republicans favors the amendment
25 democrats & 9 republicans do not favor the amendment
7 democrats & 4 republicans are unsure.
democrats=55
republicans=45
*A person is selected at a random from the sample. Find the probablity that the described person is selected.
a.) a person who doesn't favor the amendment.
b.) a republican
c.) a democrat who favors the amendment

btw where it says a.) b.) c.) those arn't answer choices... you have find what they are.

Answer 1

In the first question, the probabilities for each total are:
2 or 12: 1/36 each
3 or 11: 2/36 each
4 or 10: 3/36 each
5 or 9: 4/36 each
6 or 8: 5/36 each
7: 6/36

Probability of 7 or more =P(7) + P(8) + P(9) +P(10) + P(11) + P(12) = 6/36 + 5/36 + 4/36 + 3/36 + 2/36 + 1/36 =21/36 = 7/12

In the second question:
a) (25+9)/100 = 34/100 = 17/50 = 0.34
b) 45/100 = 9/20 = 0.45
c) 23/100 = 0.23

Answer 2

first one: possible combinations that have a sum of 7+:
1 - 6
2 - 5 or 6
3 - 4 or 5 or 6
4 - 3 or 4 or 5 or 6
5 - 2 or 3 or 4 or 5 or 6
6 - 1 or 2 or 3 or 4 or 5 or 6

I got 22/36

the second one:

there are 34 possibilites for a
there are 45 possibilities for b
there are 23 possibilites for c

so b is the most likely

Answer 3

21/36

and

0.34
0.45
0.23
You just divide the number of each by 100, the total number of people.