solve systems by substitution method 3s-4t=14 5s+t=8?

Answer 1

3s-4t = 14
5s + t = 8

t = 8-5s (solve second equation for t)

3s - 4(8-5s) = 14 (substitute {8-5s} for t in 1st equation)
3s -32+20s = 14 (Distribute 4 to {8-5s})
23s-32 = 14 (simplify)
23s = 46 (add 32 to both sides)
s = 2 (Divide both sides by 23)
t = -2 (with s=2 solve for t in either equation)

Soln: s=2, t=-2

Answer 2

from 5s+t=8, t=8-5s
Substitute this value for t into 3s-4t=14,to get
3s-4(8-5s)=14
This gives 3s-32+20s=14
23s=14+32
23s=46
s=2 Substitute 2 for s in either of
the two equations gives t
5s+t=8, 5x2+t=8, 10+t=8, t=8-10, t=-2

So, s=2 andt=-2. Check as follows:

3(2)-4(-2)=14? 6+8=14? 14=14 Correct!
5(2)+(-2)=*? 10-2=*? 8=8 Correct!
And that's all there is to it!

Answer 3

3s-4t=14 5s+t=8
Solve second equation fot getting t = 8 -5s
Now substitute ths in the first equation getting:
3s - 4(8-5s) =14
3s -32 +20s =14
23s = 46
s =2
t = 8-5s = 8-5*2= -2

Answer 4

solve for "t" in the second equation since it has no coefficient and is easiest to work with, which gives t=8-5s. Next, substitute this in for t in the first equation and solve for s.

3s-4(8-5s)=14
3s-32+20s=14
23s=46
s=2

Choose either equation and substitute 2 in for s and solve for t.

5(2)+t=8
t=-2

Answer 5

3s-4t=14

5s+t=8 ...1

3s-4t=14
-4t=14-3s
4t=3s-14
t=(3s-14)/4 ....2

2 in 1

5s+t=8
5s+(3s-14)/4=8 by 4
20s+3s-14=32 add 14
23s=46 divide on 23
s=2

substitute in eq(2)
5(2)+t=8
8-10=t=-2

t=-2, s=2

Answer 6

3s-4t=14
5s+t=8 -> t=-5s+8

3s-4(-5s+8)=14
3s+20s-32=14
combine like terms
23s-32=14
23s=46
s=2

substitute s into equation
t=-5s+8
t=-5(2)+8
t=-10+8
t=-2

Answer 7

t = 8 - 5s
3s - 4.(8 - 5s) = 14
3s - 32 + 20s = 14
23s = 46
s = 2
t = 8 - 10 = - 2
s = 2 , t = - 2

Answer 8

For the first equation:
3s-4t=14
3s=14+4t
s=(14+4t)/3
Plug this into the 2nd equation:
5((14+4t)/3)+t=8
(70+20t)/3+t=8
Multiply by 3
70+20t+3t=24
23t=-46
t=-2
Plug this into either equation to solve for s (which is=2)

Answer 9

solve for t in both equations set them equal to eachother then solve for s . put s back into either of the original equations and solve for t and ur done