how do u factor: 75(x+y)^2-108?
2007-06-24 11:26:00 · 6 answers · asked by dudu 1 in Science & Mathematics ➔ Mathematics
75(x+y)^2-108
75(x^2 + 2xy + y^2) - 108
75x^2 + 150xy + 75y^2 - 108
I just distributed it but I'm not sure how to factor..
Wasn't it already factored from the beginning?
2007-06-24 11:43:39 · answer #1 · answered by Carmen 4 · 0⤊ 0⤋
First, factor out the greatest common factor, which is 3.
3{25(x+y)^2 - 36}
Now you have a difference of squares, a^2-b^2= (a-b)(a+b), so
3{[5(x+y)-6][5(x+y)+6]}
Then I would probably simplify by distributing the 5.
3[(5x+5y - 6)(5x+5y+6)]
2007-06-24 18:51:36 · answer #2 · answered by John S 1 · 0⤊ 0⤋
75 ( x+y )^2 - 108
75 X 2 ( x + y )^ - 108
150 ( x^ + 2xy + y^ ) - 108
( 150x^ + 300xy + 150y^ ) - 108
Taking 3 common :
50x^ + 100xy + 50y^ - 36 .
2007-06-24 18:45:38 · answer #3 · answered by PartyStarter 1 · 0⤊ 0⤋
75(x+y)² - 108
3(25(x+y)² - 36)
3(5(x + y) - 6)(5(x + y) + 6)
3(5x + 5y - 6)(5x + 5y + 6)
.
2007-06-24 18:49:06 · answer #4 · answered by Robert L 7 · 0⤊ 0⤋
Let (x+y)=A, so problem becomes 75A^2-108
3(25A^2-36), 3(5A+6)(5A-6)
3( 5(x+y)+6)(5(x+y)-6)
3( 5x+5y+6)(5x+5y-6)
2007-06-24 18:47:00 · answer #5 · answered by Grampedo 7 · 0⤊ 0⤋
i have no idea!!!
2007-06-24 18:30:11 · answer #6 · answered by Anonymous · 0⤊ 2⤋