Find the product using the FOIL method.
(6y + 5)(3y + 1)
18y2 + 5
9y2 + 6
18y2 - 9y + 5
18y2 + 21y + 5
2007-06-24 09:50:35 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(6y + 5)(3y + 1)
=6y*3y +6y*1 + 5*3y +5*1
=18y^2 +6y +15y +5
= 18y2 +21y +5
2007-06-24 09:58:17 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
First (6y)(3y)
+
Outer (6y)(1)
+
Inside (5)(3y)
+
Last (5)(1)
So: 18y^2+6y+15y+5
18y^2+21y+5
2007-06-24 16:57:55 · answer #2 · answered by ΛLΞX Q 5 · 0⤊ 0⤋
http://en.wikipedia.org/wiki/FOIL_rule
FIRST: 6y times 3y = 18y^2
OUTER: 6y times 1 = 6y
INNER: 5 times 3y = 15y
LAST: 5 times 1 = 5
Then add all those answers together and get:
18y^2 + 21y + 5
2007-06-24 16:58:10 · answer #3 · answered by Wheels 3 · 0⤊ 0⤋
18y^2+6y+15y+5
18y^2+21y+5 is the answer.
2007-06-24 16:58:03 · answer #4 · answered by klynnr_1981 4 · 0⤊ 0⤋
set your last equation = to zero and use the quadratic equation
2007-06-24 16:56:15 · answer #5 · answered by Gayle B 1 · 0⤊ 0⤋