2007-06-24 08:52:02 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(-a^3)^-2/3
just multiply both the powers
u get
(-a) ^-2
since it s a -ve power it wil b taken in the denominator as +ve
= 1/ (-a)^2
opening the square
=1 / a^2
2007-06-24 08:55:43 · answer #1 · answered by sweet n simple 5 · 0⤊ 0⤋
(-a ³) ^ (-2/3)
= [(-1).a³ ] ^ (-2/3)
= 1 / [ (-1).a³ ] ^ (2/3)
= 1 / [ (-1) ^ (2/3).(a ³) ^ (2/3) ]
= 1 / a ²
2007-06-28 07:49:18 · answer #2 · answered by Como 7 · 0⤊ 0⤋
(-a^3)^(-2/3) = -(a)^(-3*2/3) = (-1)^(-2/3)* (a^3)^(-2/3)
= (-1)^(-2/3)/(a^(3*2/3)) = (-1)^(-2/3)/a^2
= 1/((-1)^(2/3)*a^2)=1/(((-1)^2)^(1/3)*a^2)= 1/(1^(1/3)*a^2)
= 1/a^2
2007-06-24 09:09:38 · answer #3 · answered by telsaar 4 · 0⤊ 0⤋
First simplify the powers:
3 x (-2/3) = -2
So the given fn is -a^-2 = -1/a^2
2007-06-24 09:00:00 · answer #4 · answered by Me & Myself 2 · 0⤊ 0⤋
this would be -a^-2 or -1/a^2...you multiply the exponents to get -a^-6/3.. then reduce the exponent -a^-2... a negative exponent is the same as the coefficient (in this case -1) over the number to the exponent (a^2)
2007-06-24 08:57:54 · answer #5 · answered by Anonymous · 0⤊ 0⤋