solve by using the quadratic formula x^2=3x+12 and x^2-x-2=0?

Answer 1

lol, do you know the quadratic formula?

you have: x^2-3x-12 = 0 and x^2-x-2 = 0. Plug the numbers in and solve!

For ax^2 + bx + c = 0, the quadratic formula states that:

x =[-b +-(plus or minus) sqrt(b^2-4ac)]/2a

Answer 2

x^2=3x+12
=> x^2-3x-12=0
Comparing with standard quadratic equation
ax^2+bx+c=0,here
a=1.b= -3 and c= -12
=>x={3+-sqrt(9+48)}/2
=(3+-sqrt57)/2 Therefore x=(3+sqrt57)/2
or (3-sqrt57)/2

x^2-x-2=0
Here a=1,b= -1 and c= -2
Therefore x={1+-sqrt(1+8)}/2
=(1+-sqrt9)/2
=(1+-3)/2=2 or -1 ans

Answer 3

Question 1
x² - 3x - 12 = 0
x = [ 3 ± √(9 +48) ] / 2
x = [ 3 ±√57 ] / 2
x = 5.27 , x = - 2.28

Question 2
x = [1±√(1 + 8)] / 2
x = [1 ± 3] / 2
x = 2 , x = - 1

Answer 4

-1

Answer 5

the 2nd one will factor... to (x-2)(x+1) = 0