2007-06-24 05:11:04 · 11 answers · asked by Montgomery M 2 in Science & Mathematics ➔ Mathematics
500
2007-06-25 08:41:58 · answer #1 · answered by James E 2 · 0⤊ 0⤋
500
2007-06-24 13:03:41 · answer #2 · answered by UNIQUE 3 · 0⤊ 0⤋
500
2007-06-24 12:55:53 · answer #3 · answered by Carley S 2 · 0⤊ 0⤋
500
2007-06-24 12:34:07 · answer #4 · answered by ? 2 · 0⤊ 0⤋
500
2007-06-24 12:15:06 · answer #5 · answered by gesges 3 · 0⤊ 0⤋
500 - 500 +500*500/500
The first two terms cancel out.
We are left with 500*500/500 = 500
2007-06-24 12:28:29 · answer #6 · answered by Swamy 7 · 0⤊ 0⤋
0+500*1=500
2007-06-24 12:19:17 · answer #7 · answered by ? 5 · 0⤊ 0⤋
Answer is 500
solve the 2nd part -> 500*500/500 = 500*(500/500)=500*1=500
the first parts of the equation are independent 500 - 500 =0
The rules of operations are first deal with parenthesis, then exponents (neither of which are in this equation)
Following are multiplication and division, then addition and subtraction
2007-06-24 12:18:11 · answer #8 · answered by Cableman 1 · 0⤊ 0⤋
Order of operations - do the multiplication and division first and then do the addition and subtraction
500-500+500*500/500
500-500+500*1
500-500+500
0+500
500
2007-06-24 12:17:09 · answer #9 · answered by whitesox09 7 · 1⤊ 0⤋
easy
1st method rel method(BDMAS (bracket->division->multiplication->adition->subraction))
500-500+500*500/500=
500-500+500*1 (500/500=1)
500-500+500 (500*1=500)
500-0 (-500+500)
=500
(or)
500-500=0
0+500=500
500*500=250000
250000/500=500
2007-06-24 12:33:02 · answer #10 · answered by santosh R 2 · 0⤊ 0⤋