One of the roots of x^2 + x - 3 = 0 is:?

Answer 1

x^2 + x - 3 = 0

x = (-1 +- sqrt(1-4*3))/2 = (-1+-sqrt13)/2

In general:
ax^2 + bx + c = 0
x = (-b+-sqrt(b^2-4ac))/2a

Answer 2

Answer for your Quadratic Equation



Your Problem is 1 x2 +1 x -3 = 0
We can solve this problem by the following methods
Note : the multiplication sign is * here to avoid confusion with x

By Using Factorization Method :
1 x2 +1 x -3 = 0
1 ( x2 -1.30277563773 x +2.30277563773 x -3 ) = 0
1 (( x2 -1.30277563773 x ) + ( 2.30277563773 x -3 )) = 0
1 ( x -1.30277563773 ) ( x +2.30277563773 ) = 0, divide both side with 1
( x -1.30277563773 ) ( x +2.30277563773 ) = 0, which is true if
( x -1.30277563773 ) = 0 OR ( x +2.30277563773 ) = 0, so we got these answers
x = 1.30277563773 OR x = -2.30277563773

By Using ABC Formula :
1 x2 +1 x -3 = 0
We have to turn it into ax2 +b x + c = 0 form, so
a=1 , b=1 , c=-3
Use the following formula :
x = (-b+(b2-4ac)(1/2))/2a OR x = (-b-(b2-4ac)(1/2))/2a, enter the value of a,b,c to this formula
x = (-1+( (1)2 - 4 * 1 * -3)(1/2))/(2 * 1) OR x = (-1-( (1)2 - 4 * 1 * -3)(1/2))/(2 * 1)
x = (-1+(13)(1/2))/(2 * 1) OR x = (-1-(13)(1/2))/(2 * 1)
x = (-1+(13)(1/2))/2 OR x = (-1-(13)(1/2))/2
x = (-1+3.60555127546)/2 OR x = (-1-3.60555127546)/2
x = 1.30277563773 OR x = -2.30277563773

Answer 3

x^2 + x - 3 = 0

Make a perfect square using first two terms and adjust the constant to get

( x + 1/2 )^2 - 1/4 - 3 = 0

( x + 1/2 )^2 = 13/4

x + 1/2 = + ( 1/2 ) root 13 or - ( 1/2 ) root 13

x = - 1/2 + ( 1/2 ) root 13 or - 1/2 - ( 1/2 ) root 13

Answer 4

You cannot factor this directly, so you need to use the quadratic formula.
a=1, b=1, c=-3 so
x = [-1 +/- sqrt(1-4*1*-3)] / 2
x = [-1 +/- sqrt(13)] / 2

Answer 5

x = [-1 +/- sqrt(1+4*3)]/2
x = -.5 +/- .5sqrt(13)
One root is -.5 + .5sqrt(13)
Other root is -.5 - .5sqrt(13)

Answer 6

x=(-1+/-sqrt(1+12))/2

x1=1.3028
x2=-2.3028

Answer 7

in decimals, it can be 1.3 or -2.3

Answer 8

-2.302775638