2007-06-24 04:33:12 · 7 answers · asked by kaspead 1 in Science & Mathematics ➔ Mathematics
3π/4 = 135 deg
=> 2 nd quadrant
2007-06-24 04:39:07 · answer #1 · answered by harry m 6 · 0⤊ 0⤋
It relies upon on the Sin. -12 is the adjacent area, 13 is the longest area. tan is opposite over adjacent. so it is going to be opposite= the sq. root of 13 squared minus -12 squared. it particularly is 5. so Tan would be 5/-12 putting it interior the 2d quadrant. that would desire to be .28 or 28 stages.
2016-11-07 08:30:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
II
3π/4 radian
2007-06-24 06:17:04 · answer #3 · answered by Mark 6 · 0⤊ 0⤋
0, pi/2, pi, and 3pi/2 separate the 4 quadrants
3pi/4= pi - pi/4 and is therefore between pi/2 and pi, which are the bounds of the 2nd quadrant
2007-06-24 04:39:14 · answer #4 · answered by whitesox09 7 · 0⤊ 0⤋
second quadrant
2007-06-24 05:39:08 · answer #5 · answered by Jpressure 3 · 0⤊ 0⤋
second quadrant
2007-06-24 04:37:19 · answer #6 · answered by Anonymous · 0⤊ 0⤋
2nd
2007-06-24 04:43:58 · answer #7 · answered by UNIQUE 3 · 0⤊ 0⤋