2007-06-24 04:23:41 · 8 answers · asked by lilphilly46 1 in Science & Mathematics ➔ Mathematics
6k^11
2007-06-24 04:30:47 · answer #1 · answered by RL 1 · 0⤊ 1⤋
= 2 x 3 x k^8 x k^3
= 6.k^11
2007-06-28 10:08:56 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Problems like these are best solved one step at a time: FIrst multiply the numbers to get 6.
Next multiply the powers of k.
When multiplying numbers expressed as exponentials with the same base (in this case k), you add the exponents: so k^8 * k^3 = k^11.
If you were to divide, you would subtract the exponents. If you were raising one to a power, you would multiply the exponents.
Thus your answer is 6 * k^11
2007-06-24 11:34:45 · answer #3 · answered by MathProf 4 · 0⤊ 1⤋
Laws of indices says that when multiplying they must be added so 6k^(8+3) = 6k^11
2007-06-24 11:32:42 · answer #4 · answered by Daniel A 2 · 0⤊ 2⤋
6k^11. You add exponents when you multiply unless it is in parenthesis.
2007-06-24 11:38:30 · answer #5 · answered by Kandice F 4 · 0⤊ 1⤋
6k^11
2007-06-24 12:42:49 · answer #6 · answered by gesges 3 · 0⤊ 0⤋
the bases r diff so the powers cannot be added
2007-06-25 01:51:07 · answer #7 · answered by Manu 2 · 0⤊ 0⤋
the base is different so you can't add the exponent
2007-06-24 11:52:54 · answer #8 · answered by UNIQUE 3 · 0⤊ 0⤋