center at (-5, -1); radius (square root of) 3
Problem is... How can you find/plot a square root?
2007-06-23 22:16:31 · 3 answers · asked by Belx2 2 in Science & Mathematics ➔ Mathematics
this is not a problem of trignonometry but co-crodinate goemetry
this is equation of a cirlce (x+5)^2 + (y-1)^2 = 3
2007-06-23 22:23:22 · answer #1 · answered by Mein Hoon Na 7 · 1⤊ 0⤋
Strike an arc or radius 2 from the x-axis. The x value of the point where the arc crosses y = 1 will be â3. Scale this off (along the y=1 line from x=0) with your compass and draw your circle with this radius.
2^2 - 1^2 = 3
2007-06-24 05:56:33 · answer #2 · answered by Helmut 7 · 1⤊ 0⤋
A general equation of a circle is in the form
(x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is equal to the radius.
h = -5, k = -1, r = sqrt(3), so
(x - (-5))^2 + (y - (-1))^2 = [ sqrt(3) ]^2
(x + 5)^2 + (y + 1)^2 = 3
You start by plotting your center as a dot (-5, -1), approximate sqrt(3) with a calculator (approximately 1.73), and measure 1.73 from the center to the north, east, south, and west of the center.
2007-06-24 05:22:22 · answer #3 · answered by Puggy 7 · 2⤊ 1⤋