2007-06-23 18:52:22 · 7 answers · asked by matcav2002 1 in Science & Mathematics ➔ Mathematics
i wrote it wrong problem is 18^3-48x^2-3x+8
2007-06-23 19:08:36 · update #1
18x³-48x²+3x+8
= 6x²·3x - 6x²·8 + 1·3x + 1·8
= 6x²(3x - 8) + 1(3x + 8) .... It won't factor
3x - 8 isn't exactly the same as 3x + 8
Addendum:
You still wrote the problem wrong
18^3-48x^2-3x+8
and it still won't factor
2007-06-23 19:04:36 · answer #1 · answered by IPuttLikeSergio 4 · 0⤊ 1⤋
Given:
18x^3 - 48x^2 - 3x +8
Factoring by grouping;
( 18x^3 - 3x ) + ( -48x^2 +8 )
solve:
[ 3x ( 6x^2 - 1 ) ] - [ 8 ( 6x^2 - 1 ) ]
factor out similar terms
answer :
(6x^2 - 1) ( 3x - 8 )
2007-06-24 02:49:48 · answer #2 · answered by James_C 2 · 0⤊ 0⤋
Most likely there is some typo here.
It is either 18x^3+48x^2+3x+8 or 18^3-48x^2-3x+8.
18x^3+48x^2+3x+8
= 6x^2(3x+8)+3x+8
= (6x^2+1)(3x+8)
18^3-48x^2-3x+8
= 6x^2(3x-8)-(3x-8)
= (6x^2 -1)(3x-8)
2007-06-24 02:12:38 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
Edit, changing post with new problem from additional information. "18x^3-48x^2-3x+8"
You can group like so:
18x^3 - 48x^2 - 3x + 8
(18x^3 - 48x^2) + (-3x + 8)
6x^2(3x - 8) - (3x - 8)
(6x^2 - 1)(3x - 8)
Thus, factoring by grouping, you get (6x^2 - 1)(3x - 8)
2007-06-24 02:11:12 · answer #4 · answered by Alex 4 · 1⤊ 0⤋
18x^3 - 48x^2 - 3x + 8 =
18x^3 - 3x - 48x^2 + 8 =
3x(6x^2 - 1) - 8(6x^2 - 1) =
(3x - 8)(6x^2 - 1) =
(3x - 8)(xâ6 - 1)(xâ6 + 1)
2007-06-24 02:17:50 · answer #5 · answered by Helmut 7 · 1⤊ 0⤋
18x^3-48x^2-3x+8 (corrected)
= 6x^2(3x - 8) - 1(3x - 8)
= (6x^2 - 1)(3x - 8)
2007-06-24 02:17:37 · answer #6 · answered by mathjoe 3 · 1⤊ 0⤋
are you sure that there is exactly one minus sign? thr should be either two or none for factoring by grouping...
2007-06-24 02:05:42 · answer #7 · answered by hipguyrockin 2 · 1⤊ 1⤋