What is the value of the acceleration of gravity on this planet?

Question

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 51.0 . The explorer finds that the pendulum completes 104 full swing cycles in a time of 145

The answer is in m/s^2. This was the entire amount of information that was given to me for the question.

Answer 1

Your question is incomplete.

what unit is the length in? cm, m? what?

and how about the time? is it seconds? minutes? hours?

For a pendulum that is 51 centimeters long, and does 104 cycles in 145 seconds, the g is about 10.42 m/s^2.

For a pendulum that is 51 meters long, and does 104 cycles in 145 minutes, the g is about .29 m/s^2.

For a pendulum that is 51 meters long, and does 104 cycles in 145 seconds, the g is 1042.08 m/s^2...

so it makes a big difference...But i'm inclined to think you mean the first one :)

hope this helps!

Answer 2

By full swing cycle I assume that you mean two swings (left to right and back again) of the pendulum.
Where T is the period (time)
l = length
g = acceleration of gravity
T = 2pi√(l/g)
Rearrange the equation to get:
g = 4pi^2(l)/T^2 = 4pi^2(51)/(145/104)^2 = 1035.76

Answer 3

Or, if riding a bicycle on earth the longer and steeper the hill the bigger the thrill.

Answer 4

acceleration due to gravity is 32.2 ft/sec^2...

what was the rest of the question?

Answer 5

3.14