If sam could do a job in 4 days that Lisa can do in 6 days, and Tom could do in 2 days, how long would the job take if Sam, Lisa, and Tom were to complete it together.
and you can explain how? Thanks.
2007-06-23 08:59:22 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Sam can do the work in 4 days.
So he does 1/4 work in 1 day.
Similarly,
Lisa does 1/6 work in 1 day
Tom does 1/2 work in 1 day.
Total 1 day work = 1/4 + 1/6 + 1/2 = 11/12
So they'll take 12/11 = 1.09 days to complete the work.
Hope this helps.
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2007-06-23 09:11:53 · answer #1 · answered by Prashant 6 · 1⤊ 0⤋
Won't give you the answer (that would be cheating), but here's how to start.
Determine what FRACTION of a job Sam can do in ONE day. Call that fraction S.
Likewise, determine what fraction of a job Lisa can do in one day, and call that L.
Do likewise for Tom, and call that fraction T.
That means the fraction of a job that all of them can finish in ONE day, if they all work together, is S+L+T.
From that, you should be able to figure out how many days it'll take them to finish the full job.
2007-06-23 16:12:32 · answer #2 · answered by RickB 7 · 0⤊ 0⤋
it's 2 > x days because if Tom can do it in 2 days why should it take longer if he has more help. If you aren't aloud to answer the question that way i'd say 1 day.
2007-06-23 16:07:21 · answer #3 · answered by Munchie 2 · 0⤊ 1⤋
i think we will take the ratio of them n the answer would be 1/3. not sure enough but i think 1/3 is correct.
OR
average
4+6+2/3= 4 days
2007-06-23 17:19:28 · answer #4 · answered by Pahuni A 2 · 0⤊ 2⤋
d = no. of days work
1/4d + 1/6d + 1/2d = 1
11/12d = 1
d = 1 / 11/12
d = 1 x 12/11
d = 1 1/11 days or 1 day, 2 hr, 10 min, 54 6/11 sec
2007-06-26 11:16:52 · answer #5 · answered by Jun Agruda 7 · 3⤊ 0⤋
tom could do it alone in 2 days.
2007-06-23 16:10:26 · answer #6 · answered by shelby n 1 · 0⤊ 1⤋
what I think the answer is is 4 days.
2007-06-23 16:15:38 · answer #7 · answered by EGO 4 · 0⤊ 1⤋