An iron ore sample is found to be 35.00% Fe by mass. How many grams of ore is needed to obtain 454.0 grams of

0 ⤊

Fe?

2007-06-23 05:22:16 · 3 answers · asked by Tone 1 in Science & Mathematics ➔ Chemistry

This is a simple ratio.

If your ore is only 35% Fe, then you need 454.0 / .35 to get the grams of ore that you need.

2007-06-23 05:25:31 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋

100/35 x 454 = 1,297 grams of ore.

2007-06-23 13:32:49 · answer #2 · answered by Norrie 7 · 0⤊ 0⤋

1297 g

2007-06-23 12:26:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋