Can you explain it as well? THanks
2007-06-23 00:44:26 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
T² = 4 pi² L / G => G = 4 pi² L / T²
(taking square of both sides and then multiplying both sides by G and dividing them by T²)
2007-06-23 00:48:26 · answer #1 · answered by ?????? 7 · 2⤊ 1⤋
T = 2pi sqrt (L/G)
=> T^2 = 4 pi^2 (L/G)
=> L/G = [T^2]/[4pi^2]
=> G = [4pi^2(L)]/[T^2]
2007-06-23 08:00:29 · answer #2 · answered by Anonymous · 1⤊ 1⤋
it is calculated from the equation of time period of a simple pendulum and it also works on a compound pendulum...
the last step in the derivation is,
T=2*pi*sqrt(L/G)
therefore,
T^2=2*2*pi*pi*L/G
&
G=2*2*pi*pi*L/(T^2)
where G is the acceleration due to gravity..
2007-06-23 08:01:31 · answer #3 · answered by braggy 1 · 1⤊ 1⤋
T^2=4pi^2L/G
4pi^2xL/T^2. answer
2007-06-23 08:25:14 · answer #4 · answered by Anonymous · 0⤊ 1⤋
T = 2Ï.â(L/G)
T/ 2Ï = â(L/G)
T ² / 4ϲ = L / G
G.T ² = 4ϲ.L
G = 4.Ï Â².L / T ²
2007-06-25 15:14:55 · answer #5 · answered by Como 7 · 1⤊ 0⤋