2007-06-22 20:33:55 · 7 answers · asked by Jess M. 1 in Science & Mathematics ➔ Physics
-40 degrees.
9/5X+32=X
X-32=9/5X
5X-160=9X
4X=-160
X=-40
2007-06-22 20:39:38 · answer #1 · answered by VICKtimize 2 · 0⤊ 1⤋
We know that 32 deg F is 0 deg C, and for each 9 degree change in F, C changes by 5 degrees.
So for n number of changes,
32-9n = 0-5n
n=8
At -40, both C and F temps are the same.
2007-06-22 20:38:54 · answer #2 · answered by cattbarf 7 · 1⤊ 1⤋
-40 C = - 40 F
Let us see how.
We know that X degrees C = x 9/5 + 32 F
So,
-40 C = -40 x 9/ 5 = -72
Adding + 32 to this we get the result as - 40 F
So, - 40 C = - 40 F
2007-06-22 21:50:09 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
- 40°C(9/5) + 32° = - 40°F
or
(9/5)x + 32 = x
9x + 160 = 5x
4x = - 160
x = - 40° (F or C)
2007-06-22 21:23:51 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
So, 28 - 32 = -4 * 5/9 = -2.22 or -2 degrees Celsius.
2016-05-18 01:15:57 · answer #5 · answered by ? 3 · 0⤊ 0⤋
At -40°
°C = (°F - 32) ÷ 1.8
-40°C = (-40 - 32) ÷ 1.8
-40°C = -72 ÷ 1.8 = -40°F
2007-06-23 05:40:12 · answer #6 · answered by Norrie 7 · 0⤊ 0⤋
-40
2007-06-26 12:19:20 · answer #7 · answered by johnandeileen2000 7 · 0⤊ 0⤋