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full of liquid soap. he then fills it with water to avoid detection. unable to resist the temptation, he steals 4 gallons of mixture again, and fills it with water. when the liquid soap is checked , it is found that ratio of soap left to that of the water is 36:13. what was the initial amount of the soap in the container. .

please explain, me in detail,
and tell me if any technique related to allegations,
how to solve this type of question.
try to solve in the shorter way.

2007-06-22 19:33:13 · 1 answers · asked by angel_hardeep 1 in Science & Mathematics Mathematics

ans should be in litres,

2007-06-22 19:33:47 · update #1

1 answers

FIRST filching: Let V be the volume of the container in gallons. After the robbery and the filling with water, the AMOUNT of soap in the container is V-4, and the fractional concentration of soap is ... V-4/V. The amount of water is 4 gallons and fractional conc is 4/V.
SECOND filching: The amount of soap taken is
4(V-4)/V, leaving (V-4)(1-4/V) as the amount behind. The amount of water taken is. The amount of water taken is 4(4/V), leaving 4-4(4/V) behind.
So to find V, 13* [(V-4)(1-4/V)] = 36*[4-4(4/V)]
You can express V in liter by multipling by 3.78.

2007-06-22 20:00:50 · answer #1 · answered by cattbarf 7 · 0 0

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