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this is the question...
A and B are two points on the same horizontal level where B is 5 km west of A. The bearing of the peak P, of a hill from B is 040* and the bearing of P from A is 300*. The angle of elevation of P from A is 25*. Find the angle of elevation of P from B.

plz show me the calculation n it diagram...
if possible sent it to my email...kanhyn@yahoo.com

2007-06-22 19:00:45 · 6 answers · asked by kanhyn 1 in Science & Mathematics Mathematics

this is the question...
A and B are two points on the same horizontal level where B is 5 km west of A. The bearing of the peak P, of a hill from B is 040* and the bearing of P from A is 300*. The angle of elevation of P from A is 25*. Find the angle of elevation of P from B.
the answer of this question is 35*32'...
all i need is calculation n diagram

plz show me the calculation n it diagram...
if possible sent it to my email...kanhyn@yahoo.com

2007-06-22 20:27:22 · update #1

6 answers

Firstly we are using compass directions for the diagram. North = 360 (up), east = 90 (right), south = 180 (down), west = 270 (left)

Draw B on the left side of page. Draw A somewhere to the right of B. Connect with line.
B is now west of A. Define the line to be 5km.

Peak P is bearing 40 degrees from B. That is, 40 degrees right of vertical or 50 degrees up from the horizontal line to A.
Similarly, P is bearing 300 from A. That is, 60 degrees left of vertical or 30 degrees up from the horizontal.

Draw lines from A to P and B to P. This will give you a triangle with sides AP, BP and AB. Side AB is length 5km. Angle BP-AB is 50 degrees. Angle AP-AB = 30 degrees.

See diagram.

Now we need to find angle P. We have 2 angles and the angles in any triangle add up to 180 degrees. Angle B = 50 degrees. Angle A = 30 degrees. Therefore angle P = 100 degrees.

We can now use the law of sines to determine the lengths/distances for AP and BP.

(Sin A)/a = (Sin B) / b = Sin P / p

Here, I will use:
a= distance BP (opposite angle A = 30 degrees)
b = distance AP (opposite angle B = 50 degrees)
p = distance AB (opposite angle P = 100 degrees) = 5km.

sin B=sin A=sin P
bap

sin P = sin 100 = 0.984808 = 0.196962 = sin 50
AB 5 5 AP

AP = sin 50
0.196962

= 0.766044
0.196962

= 3.889301

BP=sin 30
0.196962

=0.5
0.196962

=2.538561

That’s Part 1 done.

Now part 2.

Angle of elevation of P for A is 25 degrees. Draw the triangle again, this time a right angled triangle. We want to determine the height of peak P.

We know angle A = 25 degrees. We know the adjacent side AP = 3.89km

Therefore, the opposite side or the height of the peak, is found by
tan(25) = height / 3.89 (opposite / adjacent)
0.4663 x 3.89 = height = 1.81km

Now we can determine the angle of elevation for B.

Tan (B) = opposite/adjacent = height/distance BP
= 1.81/2.54
= 0.712598
Therefore angle of elevation B = 35.4736 degrees. Round up to 35.5 degrees.

email on the way with diagram and better formatting

2007-06-22 20:46:55 · answer #1 · answered by Bernie V 1 · 1 0

Oh, come on you moron... if A and B are in the same horizontal level and you have one angle of elevation, IT IS OBVIOUS that point A has the same as the other. You do not need any stupid calculation nor a diagram, you need some more brains.

Since maybe you have not completely understood the point: The answer is 25 degrees.

2007-06-22 19:19:57 · answer #2 · answered by Anonymous · 0 0

Bearings differ from angles, since zero degrees is north, and the bearing is reckoned clockwise to 360 degrees. So with the points and peak P, you have a triangle with angles of 50 degrees at B, 60 degrees at C, and 5 km for AB, the horizontal line. (East has a bearing of 90 degrees). Then angle P is 70 degrees. You need to use the law of Sines to determine BP and AP. Once you have AP, you can find the height of the hill, H, as
AP * Tan 25. Once you know that, H/BP = Tan-1 (angle of elelevation from B)

2007-06-22 19:15:18 · answer #3 · answered by cattbarf 7 · 0 0

Answer is 74 degree. I shall send you the solution in e-mail within an hour.
You are free to download study material from my free educational website www.schoolnotes4u.com.

Solution posted in e-mail.

Other members who have answered your question have misunderstood your question. 40 and 300 are distances from base of P to B and A and not angles of elevation. In fact, you have not written your question properly.

My answer is incorrect as I have misunderstood your question. I shall solve it again and send you in e-mail.

Answer given by Bernie V is correct. Good answer.

I have posted to you the correct solution with diagram in e-mail on the lines of the solution given by Bernie V.

2007-06-22 19:23:54 · answer #4 · answered by Madhukar 7 · 0 0

x^2+2x=63 Move 63 to left x^2 + 2x - 63 = 0 Factor the equation (X + 9)(X - 7) = 0 Thus, either x+9=0 or x-7 =0 This means x= -9 OR x=7 [Answer] --

2016-05-18 01:03:52 · answer #5 · answered by ? 3 · 0 0

in the second sentance believe it was answered , 40*

2007-06-22 19:11:06 · answer #6 · answered by daryl 4 · 0 0

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