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How do u do this problem x^2 -x -6 / x^2 - 4 =

2007-06-22 18:36:39 · 4 answers · asked by rusty 1 in Science & Mathematics Mathematics

4 answers

(x^2 - x - 6)/(x^2 - 4)
= [(x + 2)(x - 3)/(x + 2)(x - 2)]

Cancel (x + 2) from numerator and denominator.

You get:
(x - 3)/(x - 2)

2007-06-22 18:47:36 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0 0

factor both the denominator and the numerator

it would look like this (x+2)(x-3) / (x+2)(x-2)

btw..the denominator is a "difference of two squares"
so..other examples of difference of two squares would be:
(x^2 - 9) or (x^2 - 16) or (x^2 - 25) or (4x^2 - 4) and so on..

anyways..back to original problem, cancel like terms..in this case, the (x+2)

final answer: x-3 / x-2

hope this helps :D

2007-06-23 01:43:49 · answer #2 · answered by jo 2 · 2 0

I'd solve it but no pencil nearby! GRR.

I can tell you, though,
if this is for math class & you have a decent math teacher,
you can come in early & ask for help & it'll be no big.

OR, just call and ask a friend.

2007-06-23 01:51:54 · answer #3 · answered by Mighty 3 · 1 1

FOIL

(x -3)(x+2) / (x+2)(x-2)

x+2s cancel

so x - 3 / x - 2 i believe?

2007-06-23 01:42:38 · answer #4 · answered by Anonymous · 0 2

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