If x=0 then y must equal 1
0 + 4(1)=4
if y=0 then x must equal 4
4+4(0)=4
Your intercepts are
(0,1)(4,0)
Hope that helps.
2007-06-22 16:42:31
·
answer #1
·
answered by Anonymous
·
0⤊
1⤋
When x = 0 , y = 1 gives (0,1) is y intercept
When y = 0 , x = 4 gives (4,0) is x intercept.
2007-06-23 10:11:29
·
answer #2
·
answered by Como 7
·
0⤊
0⤋
set x = 0
then 0 + 4y = 4 ==> y = 1
set y = 0
then x + (4 x 0) = 4 ==> x = 4
then x = 4 and y = 1
2007-06-22 23:50:46
·
answer #3
·
answered by miraclebeliever99 4
·
0⤊
1⤋
To find the y-intercept, you have to solve for y. First you have to get y on one side, like this.
4y = -x + 4
then, divide by 4.
y = -1/4x + 1
The y-intercept is 1.
To find the x-intercept, you have to solve for x. First you have to get x on one side, like this.
x = -4y + 4.
The x-intercept is 4.
Hope this helps! =]
2007-06-22 23:40:27
·
answer #4
·
answered by Pikajane 3
·
0⤊
1⤋
To find the x intercept, plug 0 in for y and solve for x.
To find the y intercept, plug 0 in for x and solve for y.
2007-06-22 23:44:29
·
answer #5
·
answered by Kate 3
·
0⤊
1⤋
x + 4y = 4
4y= 4 - x
divide by 4
y= 1 - .25x
y int = y(0) = 1-.25(0) = 1
y = 1- .25x
0 = 1- .25x
-1= -.25x
multi by -4
x=4
2007-06-22 23:45:02
·
answer #6
·
answered by Drew 2
·
0⤊
0⤋
Don't you just make x=0 to find the y and y=0 to find the x, or is that to find something else.
2007-06-22 23:37:32
·
answer #7
·
answered by koutetsu12 3
·
0⤊
0⤋
make right hand side =1
to do so divide the equation by 4.
x/4 + y =1
the denominator of x and y are their intercepts
x int = 4; y-int=1
this comes from the formula x/x-int + y/y-int =1
2007-06-22 23:54:03
·
answer #8
·
answered by maniacker 1
·
0⤊
1⤋
yint= 1
xint= 4
2007-06-22 23:37:07
·
answer #9
·
answered by Anonymous
·
0⤊
1⤋
yint - 1
xint - 4
2007-06-22 23:46:40
·
answer #10
·
answered by *Thinker*Babe* 2
·
0⤊
1⤋