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10 answers

We can already simplify it :
(-12 z^4 * y^2 ) / (-2 z^10 * y^2)
= (6 z^4 * y^2 ) / (z^10 * y^2)
= (6 y^2 ) / (z^6 * y^2)
= 6 / z^6
Everything that is a factor at both numerator and denominator can be extracted. That is the key...

After that, what do you want to do with it?

2007-06-22 15:13:42 · answer #1 · answered by Kilohn 3 · 1 0

Divide like terms in numerator and denominator.
Numbers:-12/-2 =6
Variables: y^2/y^2 =1

you're left with 6x^4 /z^10

oops -- There's a z in the numerator (not x as I wrote it down)
z^4/z^10 = z^4 - 10 = z^-6 or 1/z^6
NOW you have 6/z^6 or 6z^-6 Just like everybody else!

2007-06-22 15:14:33 · answer #2 · answered by davec996 4 · 0 0

The rule when dividing variables with exponents is to subtract the exponents: e.g., x^6/x^4 = x^(6-4) = x^2. Of course, like variables go together, so you'll get

6z^-6y^0

The negative exponents become positive and go to the denominator. The zero exponent makes the whole factor a 1.

6/z^6

2007-06-22 15:15:36 · answer #3 · answered by Tony The Dad 3 · 1 0

Divide coefficients, subtract exponents (of the same variable).

Dividing coefficients: -12 / -2 = 6

Subtracting exponents z^4 / z^10 = z^-6 and y^2 / y^2 = y^0 = 1

the result is then 6z^-6 = 6/z^6

2007-06-22 15:15:15 · answer #4 · answered by gp4rts 7 · 1 0

im unsure in case you typed the question wisely however the subject stated is 5 and one 0.5 accelerated via 3 . for persons in simple terms beginning those math equations the main suitable action is to first examine the question heavily and ascertain which you comprehend what the subject is calling. subsequently the long thank you to do it may be to transform 5 a million/2 right into a fragment and not a quantity and a fragment (so 5 x 2 + a million) is going on maximum superb and the two proceed to be at backside for this reason eleven/2 x 3 , remember whilst multiplying fractions in basic terms the main superb quantity is used for this reason 33/2 now remember that the / sign means divide so then 33 divide via 2 is sixteen with one left over which means sixteen a million/2 practice changing fractions and likewise multiplying and dividing fractions and you will get the carry of it .in case you elect extra motives in simple terms ask i will attempt to describe as maximum suitable as i will

2016-10-18 10:27:20 · answer #5 · answered by ? 4 · 0 0

In the top of your fraction, you have negative twelve times zee to the fourth times wye squared. In the denominator, you have negative two times zee to the tenth power times wye squared. If you reduce the numbers, the negatives and numbers cancel and you are left with 6 in the top. The z^4 cancels with the z^10 and you are left with z^6 in the bottom. The y^2 over y^2 cancel out completely leaving nothing. So your final answer is: 6/z^6
Hope this helps.

2007-06-22 15:18:59 · answer #6 · answered by Lee 3 · 0 0

Note:
a^m / b^n = a^(m - n); a^0 = 1; a^-m = 1 / a^m


(-12z^4y^2) / (-2z^10y^2)

= (-12 / -2)(z^(4 - 10))(y^(2 - 2))

= 6(z^-6)(y^0) =

6
------
z^6

2007-06-22 15:13:56 · answer #7 · answered by mathjoe 3 · 0 0

-12z^4 * y*2/(-2 z^10 * y^2) = 12/2 * z^4/z^10 * Y^2/Y^2
= 6 * z^(4-10) * y^(2-2)
= 6*z^(-6) * y^0
= 6*z^(-6)

2007-06-22 15:20:19 · answer #8 · answered by telsaar 4 · 0 0

-12/-2 = 6
z^4/z^10 = z^-6 = 1/z^6 (you just subtract exponents)
y^2/y^2 = 1
so put together the answer is
6/z^6

2007-06-22 15:14:27 · answer #9 · answered by Anonymous · 0 0

go to yahoo homework help

2007-06-22 15:11:28 · answer #10 · answered by askkate2000 4 · 0 1

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