The derivative of e^x is just e^x dx, the same thing. but when you have something else in the exponent you have to apply the chain rule. So it's the derivative of e^(5x) times the derivative of 5x. This gives you y' = 5e^(5x).
I'm assuming here that you meant e^(5x) and not (e^5)x. If it's the latter, then yes, the derivative would just be e^5 because this is just a constant times x.
2007-06-22 12:21:02
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answer #1
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answered by Anonymous
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derivative of e^5 times[x] =e^5 now derivative of exp 5x-x=0 then e^0=1 then your der.. is e^5 times 1=?.done
2007-06-22 12:48:05
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answer #2
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answered by Enrique v 3
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Don't freak out, e is a constant, you are not going to do anything with it.
y=e^5x
y= (5x)'(e^(5x))
y'= 5 (e^(5x))
Get a TI-92, they do integrals, derivatives and most of all of calculus problems.
Best!
2007-06-22 12:27:12
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answer #3
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answered by titti 2
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I've put a beautifully formatted PDF at the link below. It looks as it would in a textbook. Take a look. Just give it a second to load.
http://www.tomsmath.com/step-by-step-instructions-for-finding-the-derivative-of-e-to-the-5x.html
2014-06-05 09:43:40
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answer #4
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answered by ? 3
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Rem : d/dx(e^u) = u' e^u
S0 d/dx [ e^5x] = 5 e^5x
Assuming that (5x) is the power of e
2007-06-22 12:23:29
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answer #5
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answered by a_ebnlhaitham 6
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Derivative Of E
2016-10-05 09:16:42
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answer #6
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answered by ? 4
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let u = 5x
du/dx = 5
y = e^u
dy/du = e^u
dy/dx = dy/du X du/dx
dy/dx = e^u X 5
dy/dx = 5.e^(5x)
2007-06-26 10:59:36
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answer #7
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answered by Como 7
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