How many F- ions are present in 2.50 moles of BaF2?
The correct answer is 3.01e24, but I have no clue on how to come up with this answer?
2007-06-22 08:14:36 · 3 answers · asked by JMEB 2 in Science & Mathematics ➔ Chemistry
In 2.50 moles of BaF2 there are 2.50 moles of Ba2+ and 2.50 x 2 = 5.00 moles of F-
In 1 mole there are 6.02 x 10^23 particles
6.02 x 10^23 x 5.00 = 3.01 x 10^24
2007-06-22 08:20:44 · answer #1 · answered by Dr.A 7 · 2⤊ 0⤋
Each mole of BaF2 has 2 moles of F- ions. So, 2.5 moles of BaF2 will have 5 moles of F- ions. Then, multiply 5 moles by Avogadro's number (6.02 X 10^23) to get the number of F- ions.
2007-06-22 08:29:07 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋
in each mole of BaF2, 1mole of Ba(+) & 2 moles of F(-) are present.
=> in 2 .5 moles of BaF2, 5 moles of F(-) ions are present.
in each mol , 6.023 * 10^23 F(-) ions are present
=> in 5 moles , 5 * 6.023 * 10^23 F(-) ions are present
=> 3.0115 * 10^24 F(-) ions are present
2007-06-22 08:33:22 · answer #3 · answered by s0u1 reaver 5 · 0⤊ 0⤋