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1. Key in the first three digits of your phone number (NOT the Area code)
2. Multiply by 80
3. Add 1
4. Multiply by 250
5. Add the last 4 digits of your phone number
6. Add the last 4 digits of your phone number again.
7. Subtract 250
8. Divide number by 2

Assuming your phone number was 234-5678

2007-06-22 08:02:46 · 9 answers · asked by Tiff 5 in Science & Mathematics Mathematics

9 answers

Let x = prefix and y = last 4

(250(80x+1)+2y-250)/2

(20000x + 250 + 2y - 250) / 2 carry out first order of multiplication

(20000x + 2y) / 2 combine like terms

10000x + y complete indicated division

2007-06-22 08:17:06 · answer #1 · answered by Anonymous · 0 0

1. Equation = 234
2. Equation = 234 * 80 = 18720
3. Equation = (234 * 80) + 1 = 18721
4. Equation = ((234 * 80) + 1) * 250 = 4680250
5. Equation = ((234 * 80) + 1) * 250 + 5678 =4685928
6. Equation = ((234 * 80) + 1) * 250 + 5678 + 5678 = 4691606
7. Equation = ((234 * 80) + 1) * 250 + 5678 + 5678 - 250 = 4691356
8. Equation = (((234 * 80) + 1) * 250 + 5678 + 5678 - 250)/2 = 2345678


2345678

2007-06-22 09:59:04 · answer #2 · answered by buoisang 4 · 0 0

((234*80+1)*250+5678+5678-250)/2
or ((234*80+1)*250+2*5678-250)/2
(instead of adding the last 4 twice, just multiply by 2

this simplifies to your original phone number, no matter what that number is.

2007-06-22 08:10:15 · answer #3 · answered by nemahknatut88 2 · 0 0

Let a = first three digits and b = last 4 digits, then
answer = ((a*80+1)*250+2*b -250)/2 = 10000a +b.
So, your telephone number 234-5678 becomes 2345678.

2007-06-22 08:23:37 · answer #4 · answered by ? 5 · 0 0

z = (250 * (80x + 1) + 2y - 250) / 2
z = (20000x + 250 + 2y - 250) / 2
z = (20000x + 2y) / 2
z = 10000x + y

x is the first 3 digits, y is the last 4.

Therefore, the solution just shifts the first 3 digits over 4 places and adds the last 4 digits, to get the phone number.

2007-06-22 08:08:25 · answer #5 · answered by GenoLV 2 · 2 0

(((X)(80)+1)(250) + Y + Y -250)/2
(20000X+250+2Y-250)/2
(10000)(X)+Y
if X = 234 and Y = 5678
2340000+5678=2345678

2007-06-22 08:14:51 · answer #6 · answered by skipper 7 · 0 0

((250 * (80 * (100a + 10b + c) + 1)) + (2000d + 200e + 20f + 2g) - 250) / 2

((250 * (8000a + 800b + 80c + 1)) + (2000d + 200e + 20f + 2g) - 250) / 2

(2000000a + 200000b + 20000c + 250) + (2000d + 200e + 20f + 2g) - 250) / 2

(2000000a + 200000b + 20000c + 2000d + 200e + 20f + 2g)/ 2

1000000a + 100000b + 10000c + 1000d + 100e + 10f + g

The answer is your phone number.

2007-06-22 08:12:06 · answer #7 · answered by TychaBrahe 7 · 0 0

This helps because the bottom part of the equation 9y^2 - 4 into (3y-2) (3y+2), and therefore you can cancel out the (3y+2) on the top with the (3y+2) on the bottom. Your final answer will then be: (2y-3) / (3y-2). Hope this helps!!

2016-03-14 05:40:17 · answer #8 · answered by Anonymous · 0 0

[{[[(237)(80) +1](250)] +5678(2)}-250]/2=2,345,678
234-5678

2007-06-22 08:09:03 · answer #9 · answered by Lenore P 3 · 0 0

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