Can you find the currents across the 4 resistors and ammeter?

Question

Given that
V: = 16.00 V
R2 = R3 = R5 = 4.000 ohms
R6 = 6.000 ohms

find the currents through the four resistors and ammeter in the following circuit:

http://www.geocities.com/trunks11111/ammeter.jpg

Answer 1

For practical purposes, it is generally assumed that the resistance of an ammeter is zero for DC circuits in equilibrium.

Therefore, the ammeter will be modeled as a short for the first part of the solution

the equivalent parallel resistance of R2 and R3 is 2 ohm
and R5 and R6 is
2.4 ohms

the current out of the supply is
16/(4.4)
or 4/1.1
Since R2=R3, then the currents are equal through each.

since the voltages across R5 and R6 are equal due to the shorting effect of the ammeter, this voltage is
2.4*4/1.1

The current through R5 is
2.4*4/(1.1*4)
or
2.4/1.1
since the current through R2 is
2/1.1
then the current through the ammeter is
.4/1.1 amps

Check
The current through R6
2.4*4/(1.1*6)
or
1.6/1.1 Amps
The current through R3 is
2/1.1
so the current through the ammeter is
.4/1.1 Amps

It checks

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Answer 2

hi footiemad, first you connect a twine to the helpful polarity (generally crimson colour) of the battery. the different end is hooked as much as an ammeter that too the helpful terminal (crimson colour). Now to destructive terminal a twine is connected and its different end to a variable resistor (rheostat). The some distance end of rheostat is connected with a twine and its different end to the experimental resistor whose fee is to be found out. Now from the different end of the resistor yet another twine and its different end to the destructive of the battery. series circuit is performed. Now around the experimental resistor connect the voltmeter. right here as quickly as lower back the helpful and the destructive terminals of voltmeter are linked exact. If not, then deflection could circulate opposite in the voltmeter. Now aligning the rheostat a modern-day say 0.5 ampere is made flow by way of the resistor and the voltage in the process is referred to stunning from voltmeter examining. this would be repeated by potential of various the region of the rheostat. In each degree, modern-day is referred to and its corresponding voltage is referred to. Now each and all the readings are tabulated. In each trial, V/I is calculated and it is generally almost the comparable. If mandatory the everyday of V/I ie R is located out. it is how we come across the resistance fee of the given resistor utilising an ammeter and voltmeter.

Answer 3

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