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3^(x^2 + 2x) = 27

2007-06-22 07:15:43 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Take log base 3 of both sides and I think you'll find it much easier to solve

2007-06-22 07:25:54 · answer #1 · answered by dogsafire 7 · 0 0

3^(x^2 + 2x) = 27 = 3^3
x^2 + 2x - 3 = 0
(x+3)(x-1) = 0
x = -3, 1

2007-06-22 07:26:09 · answer #2 · answered by sahsjing 7 · 1 0

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