how many ml hydrochoric acid need for provided 3% hydrochloric acid in 1L from 37%hydrochloric acid ?

Question

37% hydrochoric acid 2.5L
density=1.18g/l

Answer 1

I will answer, and I assume the 37% HCl you use to dilute is calculated as wt/ vol. If so, you don't need the density information or the total vol of 37% HCl available, (as long as it's enough to make the desired dilution).

It is a simple dilution:

37% HCL = 370mL per 1000mL

The calculation is:

(X) (37%) = (1000mL) (3%) Solve for x now:


(X) = (1000mL) (3%)
____________ The % units cancel out and
(37%) you are left with:

(X) = 81.08 mL then dilute to 1000mL with H2O. BUT REMEMBER: Until you add the final few mLs of H2O, ALWAYS ADD ACID TO WATER (.....jUST LIKE YOU "AUGHTA")

Answer 2

Weight % is mass/quantity With a 37% answer you have 37kgHCl/L you pick 3kgHCl/L M1V1 = M2V2 you may desire to the two (37)(a million) = (V)(3) V= 12.3333L <------- dilute 37% to twelve.33333L entire quantity or M1V1 = M2V2 (37)(V1) = (3)(1L) V = .08108L = 80 one.08mL <------- take this a lot of 37% and dilute to 1L entire quantity in the journey that your certainly doing this, you mostly upload acid to water slowly in case you upload water to acid it generates a lot of warmth and could splash playstation relies upon what form of % answer, you've gotten %quantity, %mass, %mole, or in my occasion weight % this is kg/L of answer. it is what's utilized in drugs like IV drips, additionally in chem labs, in many cases it is going to say which % answer is given.

Answer 3

3/37 or 81.1 ml.

Answer 4

Please can you tell me if % is by mass or by volume?