The first athlete's contract has a 1/3 probability of being assigned to each of teams A, B and C. So does the second athlete's contract. So there are 9 possibilities, each with probability 1/9:
AA, AB, AC, BA, BB, BC, CA, CB, CC
where the first letter represents the first athlete's contract and the second letter represents the second athlete's contract.
Corresponding values for Y1 are
2, 1, 1, 1, 0, 0, 1, 0, 0
and for Y2 are
0, 1, 0, 1, 2, 1, 0, 1, 0
So we get the following table for the joint PDF:
Y1\Y2 . 0 . . 1 . . 2
. 0 . . 1/9 . 2/9 . 1/9
. 1 . . 2/9 . 2/9 . 0
. 2 . . 1/9 . . 0 . . 0
and F(1, 0) = 2/9.
2007-06-20 19:42:21
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answer #1
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answered by Scarlet Manuka 7
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