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I have a mth final on friday and I am afraid I will fail if I don't understand this:( can you please help me)

x+5
---------------
-x^2-7x-10

2007-06-20 18:56:24 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

x+5
---------------
-x^2-7x-10

x+5
---------------
-(x+5)(x+2)

-1
---------------
(x+2)

2007-06-20 18:59:00 · answer #1 · answered by sweet n simple 5 · 0 0

Answers with Solutions

Qns. 1:

= ( x + 5 ) / -x² -7x -10
= ( x + 5 ) / ( x + 5 )( -x - 2 )
= 1 / ( -x - 2 )

Hope This Solutions Will Help In Answering Your Questions ;)

G0n9 G0n9™
Mathematician

2007-06-21 03:40:32 · answer #2 · answered by Kelvin 2 · 0 0

= - (x + 5) / (x² + 7x + 10)
= - (x + 5) / (x + 5).(x + 2)
= - 1 / (x + 2)

2007-06-21 02:37:55 · answer #3 · answered by Como 7 · 0 0

Whenever you are asked his type of question, they are essentially asking you to factor the denominator.

In this case, as the numerator is x+5 it is probably a good bet that x+5 is one of the factors in the denominator.

As you can see,
-x^2-7x-10 => -(x^2+7x+10) => -(x+5)(x+2) it is!

Therefore, looking at the whole equation.....

x+5
___________
-(x+5)(x+2)

Now you can simplify, since (x+5)/(x+5) = 1, your answer will be:

-1
__
(x+2)

2007-06-21 01:59:19 · answer #4 · answered by sharky.mark 4 · 0 1

Ans is :

-x^2 - 7x - 10 = -(x^2 + 7x + 10) = -(x+2)(x+5)

So,

(x+5) / ( - (x+2) (x+5) ) = - 1/ ( x+2) QED

2007-06-21 02:03:51 · answer #5 · answered by Maxis 2 · 0 0

consider the denominator

-x^2-7x-10
= -(x^2+7x+10)
= -(x^2+2x+5x+10)
= -[x(x+2) + 5(x+2)]
= -(x+2)(x+5)

now,
x+5
---------------
-x^2-7x-10

=-(x+5)/(x+2)(x+5)
on cancelling x+5 ,
=-1/(x+2)

2007-06-21 02:07:47 · answer #6 · answered by may_5 2 · 0 0

take a negative 1 out of the bottom then factor it. (x+5)(x+2) then cross out the (x+5) s and you are stuck with -1 over (x+2)

2007-06-21 02:06:58 · answer #7 · answered by ♥Summer♥ 2 · 0 0

x+5
---------------
-(x^2+7x+10)

x+5
---------------
-(x+5)(x+2)

= -1/(x+2)

2007-06-21 02:01:36 · answer #8 · answered by PaeKm 3 · 0 0

Limit.

2007-06-21 02:02:07 · answer #9 · answered by Tuncay U 6 · 0 0

1
______
-(x-2)

2007-06-21 02:02:41 · answer #10 · answered by Midor1 1 · 0 0

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