Please show mw what I did wrong-my answer is coming out 0=0
-X+3-2(X-2)=-3X-7
-X+3-2X+4=-3X-7
-3X+7=-3X-7
0=0
2007-06-20 12:46:45 · 7 answers · asked by david c 3 in Science & Mathematics ➔ Mathematics
Its is an contradiction. No answer will work because 7 does not equal -7
2007-06-20 12:51:24 · answer #1 · answered by gfulton57 4 · 1⤊ 0⤋
Your last line is wrong, but the one above it is correct.
-3x + 7 = -3x - 7
7 = -7
Since this is a FALSE statement, there is no solution.
In the future, if you get an answer like 0 = 0, then you have something called an "identity". EVERY number you put in place of x should "work". So it would not be "no solution", but rather, everything is a solution. We right this as:
{x I x is a real number}
I hope this helps!
2007-06-20 12:57:27 · answer #2 · answered by math guy 6 · 0⤊ 0⤋
it comes out to 0=-14 so its no solution
2007-06-20 13:00:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
-X+3-2(X-2)=-3X-7
+X +X
3-2(X-2)=-2X-7
3-2X+4=-2X-7
-2X+3+4=-2X-7
-2X+7=-2X-7
-7 -7
-2X=-2X-14
then you simplify, which i think would be an infinate solution (you can put any number in it)
2007-06-20 13:13:32 · answer #4 · answered by Tiffany D 1 · 0⤊ 0⤋
Use PEMDAS to do your operations in the correct orders.
P = parentheses
E = exponents
M = multiplication
D = division
A = addition
S = subtraction
2007-06-20 12:52:26 · answer #5 · answered by Lady Geologist 7 · 0⤊ 2⤋
Your work looks right. There is no solution.
2007-06-20 12:52:06 · answer #6 · answered by fcas80 7 · 0⤊ 1⤋
is that the original question?
2007-06-20 13:00:28 · answer #7 · answered by superJoel 2 · 0⤊ 0⤋