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I do not understand how to do this math promlem
-6=-(x-5)-3(5+2x)-4(2x-4)

2007-06-20 12:41:20 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

-6= -(x-5) -3(5+2x) -4(2x-4)
do the parenthesis multiplication first
-6= -1x+5 -15 -6x -8x +16
combine like terms
-6= (-1x -6x -8x) (+5 -15 +16)
-6= -15x +6
-12= -15x

-12/-15= x neg/neg cancells out
4/5 = x subs 4/5 for x back into eq. for proof

2007-06-20 13:07:22 · answer #1 · answered by Bob S 1 · 0 0

First, write down the problem
-6 = -(x-5) -3(5+2x) -4(2x-4)

Then multiply out the middle term
-6 = -(x-5) -15 -6x -4(2x-4)

And the last term:
-6 = -(x-5) -15 -6x -8x +16

Remove the parenthesis from the first term:
-6 = -x +5 -15 -6x -8x +16

Collect terms in "x"
-6 = -x -6x -8x +5 -15 +16

Do the additions"
-6 = -15x +6

Add 6 to each side
-6 + 6 = -15x + 6 +6
0 = -15x + 12

Subtract 12 from each side
0 -12 = -15x + 12 -12
-12 = -15x

Divide each side by 15
-12/15 = -15x / 15
-4/ 5 = -x
x = 4/ 5 = 8/10 = 0.8

Check:
-6 ?= -(0.8 - 5) - 3(5 + 1.6) - 4(1.6 - 4)

2007-06-20 19:56:38 · answer #2 · answered by morningfoxnorth 6 · 0 0

Get rid of all parentheses:

-6 = -(x-5) -3(5+2x) -4(2x-4)
-6 = -x+5 -15-6x -8x+16

Combine like terms:

-6 = -15x +6
15x = 12
x = 12/15 = 4/5

2007-06-20 19:48:02 · answer #3 · answered by fcas80 7 · 0 0

-6=-(x-5)-3(5+2x)-4(2x-4)

remove the brackets,
-6 = - x + 5 - 15 - 6x - 8x + 16
-x - 6x - 8x = -6 - 5 + 15 - 16
15x = 12
x = 12/15 = 4/5

2007-06-20 20:25:44 · answer #4 · answered by jurassicko 4 · 0 0

-6=-(x-5)-3(5+2x)-4(2x-4)
-6 = -x +5 -15 -6x -8x +16
-6 -5 +15 -16 = -x -6x - 8x
-12 = -15x
-12/-15= 4/5 = x

2007-06-20 19:47:34 · answer #5 · answered by ironduke8159 7 · 0 0

-6= -(x-5)-3(5+2x)-4(2x-4)
-6=(-x+5)-15-6x-8x+16
-6=-x+5-15-6x-8x+16
-6=-15x+6
12=-15x
12/-15=x or x=4/-5

2007-06-20 19:52:49 · answer #6 · answered by naval_officer 2 · 0 0

First distribute to eliminate the parentheses. Then add like terms, then get x on one side by itself. Good luck.

2007-06-20 19:47:23 · answer #7 · answered by Anonymous · 1 0

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