Can you help me factor the following math problem?

Question

here it is:

(x +1)^3(4x-9) – (16x+9)(x+1)^2

if you can...please explain. Thanks!!!

Answer 1

(x + 1)^3 (4x - 9) - (16x + 9)(x + 1)^2

The greatest common monomial is (x + 1)^2; factor that out.

(x + 1)^2 [ (x + 1)(4x - 9) - (16x + 9) ]

Simplify.

(x + 1)^2 [ 4x^2 - 9x + 4x - 9 - 16x - 9 ]
(x + 1)^2 [ 4x^2 -21x - 18 ]

Answer 2

this could be a trick question no longer with the aid of content cloth, yet with the aid of assumed answer. there is not any lacking greenback. The section that everybody messes up on is the equation. that's actual that $9 x 3= $27 and that the bell boy has $2, yet you may no longer upload ($27 + $2) at the same time. Why? with the aid of fact, If the bell boy is given $5 returned, and he wallet $2, then there is completely $3 left. The bell boy then divides that $3 into 3 (for all of the adult adult males). which means each and each guy gets $one million, no longer $3, which equals $3 funds returned in finished. So, the quantity lacking is $2, which the bell boy already has. Plus, the value of the lodge is not any longer $30 yet $25. to that end, the breakdown is as follows: the value of the lodge is $25 ($30-$5). The bell boy has $2. each and all of the adult adult males have $one million = $3 in finished. 25 + 2 + one million+ one million + one million = 30. no longer something lacking, nevertheless $30.

Answer 3

first i will factor the (x+1) term and there is at least 2 in each so
(x+1)^2 [(x+1)(4x-9)-(16x+9)]]
looking inside the brackets, i notice that there is nothing else that can be factored. expanding it will only make things worse. So the above is your solution.

Answer 4

GCF = (x+1)^2 so -----> (x+1)^2 [ (x+1)(4x-9) - (16x+9) ]

(x+1)^2 [ (4x^2 - 9x +4x -9) - (16x +9) ]
(x+1)^2 [ (4x^2 - 5x - 9) -16x-9 ]
(x+1)^2 [ 4x^2 - 21x - 18) ]
(x+1)^2 [ (4x + 3)( x - 6) ]

Answer 5

(x+1)^2[(x+1)(4x+9)-(16x+9)]

you factor out the (x+1)^2

Answer 6

(x +1)^3(4x-9) – (16x+9)(x+1)^2
= (x+1)^2[x+1)(4x-9) -(16x+9)]
= (x+1)^2[4x^2-5x -9 -16x -9)
=(x+1)^2[4x^2 -21x -18)]
=(x+1)^2(4x+3)(x-6)