2007-06-20 10:30:39 · 7 answers · asked by klemaster07 1 in Science & Mathematics ➔ Mathematics
Two.
-9 and 9
Explanation:
sqrt(t^2) = 9
Square both sides
t^2 = 81
Now take the square root of both sides
t = -9 or 9
Check:
t = -9
sqrt[(-9)^2]
= sqrt(81)
= 9
Ok
t = 9
sqrt(9^2)
= sqrt(81)
= 9
Ok
2007-06-20 10:36:08 · answer #1 · answered by MsMath 7 · 1⤊ 1⤋
The square root of some number is 9.
That number is 81.
A number squared is 81.
The square of 9 and the square of -9 equal 81.
Answer: There are two solutions.
2007-06-20 11:01:20 · answer #2 · answered by mathjoe 3 · 1⤊ 0⤋
t^2 = 9
Take the square root of both sides to get:
t = sqrt(9)
The square root of 9 is either 3 or -3, so the equation has two solutions:
t=3 or t=-3
2007-06-20 10:39:16 · answer #3 · answered by Anonymous · 0⤊ 1⤋
sq. the two facets (2x + 7)^2 = 17x + 40 3 4x^2 + 28x + 40 9 = 17x + 40 3 4x^2 + 11x + 6 = 0 (4x + 3)(x + 2) = 0 x = (-3/4, -2) the two solutions artwork once you sub and verify x^2 + 16x + sixty 4 = 15x + seventy six x^2 + x - 12 = 0 (x + 4)(x - 3) = 0 x = (-4, 3) the two solutions verify x^2 - 8x + sixteen = -9x + 28 x^2 + x - 12 = 0 (x + 4)(x - 3) = 0 x = (-4, 3) neither answer works no answer
2016-12-08 14:51:20 · answer #4 · answered by meran 4 · 0⤊ 0⤋
sqrt (t^2) = 9
square both sides
t^2 = 81
take a square root
t = 9 or -9
two solutions
2007-06-20 10:39:01 · answer #5 · answered by 7 · 1⤊ 1⤋
t² = 9
t = ± 3
2007-06-20 10:58:48 · answer #6 · answered by Como 7 · 0⤊ 1⤋
Sorry my calculator doen't have the letter t.
LOL
2007-06-20 10:36:04 · answer #7 · answered by Manny G. 2 · 0⤊ 2⤋