A supertanker spilled a total of 143,874 barrels of oil. How many liters would this be? Given 1 barrel = 42.0 gal; 1 gal = 4 quarts and 1 quart = 9.46x10-4 m3?
The pressure exerted on a substance is 17.218 g/(m*s2). What is the pressure in kg/(nm*cs2)?
2007-06-20 09:35:01 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
1 barrel = 42.0gal
(143,874 barrels) x (42 gal) = 6,042,708 gal
6,042708 gal = 22874138.070471 Liters
go to to check your answer http://www.coleparmer.com/techinfo/converters/commcapacityvolume.asp
Also for the 1st question if you have a scientific graphing calculator you should have a conversion function (usually a button on the calculator) where you enter the number and choose the type of conversion.
Hopefully the answer to the 1st question helps. Good Luck
2007-06-20 11:01:34 · answer #1 · answered by cRiMiNgEr 2 · 1⤊ 0⤋
Note: 1 L (liter) = 1 dm3
143,874 barrels * 42 gal/ barrel * 4 quarts/ 1gal *
9.46x10-4 m3/ 1 quart * 1000 dm3/ 1 m3 * 1L/ 1 dm3 =
2.29x107 L
2.29x107 L means 2.29 times 10 to the exponent 7
17.218 g/ (m*s2) * 1kg/ 1000g * 1m/ 10-9 nm *
1s2/ 10000cs2 = 1721.8 kg/ (nm*cs2)
Hope this help!
Good luck!
2007-06-20 17:34:25 · answer #2 · answered by Jennifer001 2 · 1⤊ 0⤋
143,874bbl x 42gal/1bbl x 4qt/1gal x 0.26L/gal = 6.3 million L
Cubic meters per quart seems unnecessary, so I put in L/gal. Also, because gal/bbl is given to two significant figures, that's all I reported.
2007-06-20 17:30:14 · answer #3 · answered by steve_geo1 7 · 0⤊ 1⤋