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Question

two elevators leave the tenth floor going down at the same time.the faster elevator takes 45 seconds between floors. the slower one takes 1 minute between floors. there are people on every floor waiting to go down. the first elevator that reaches each floor must stop to pick up passengers.it takes 3 minute for either elevator to stop and pick up passengers.which elevator will reach the first floor first

the faster elevator stops for 3 MINUTES the slower has to stop at the next one FLOOR 8. then the one that was on the 9th floor goes to the 7th then 5th then 3rd the 1st. the one on floor 8 stops on 6 4 2 and 1

Answer 1

The faster elevator will reach the first floor first. It will take 1115 seconds. The slower elevator will reach the first floor in 1260 seconds.

They both start out on the 10th floor. The faster elevator will reach the 9th floor first, and then have to wait 3 minutes. In that time, the slower elevator will reach the 8th floor (120 seconds). It will then have to wait 3 minutes. While the slower elevator is waiting on the 8th floor, the faster elevator will go by that floor and stop on the 7th floor, waiting there for 3 minutes...

Continue this until you have your answer (above).

Answer 2

Based on the conditions of your question, the faster elevator will reach the first floor faster. At each floor, the elevators will be alternating stops due to the time loading/unloading, and the number of floors is so few, the slower elevator does not have any instances of skipping more than one floor.

The time required for each to reach the first floor is as follows: the faster elevator will take 18:45 to reach the ground floor, the slower one will take 21:00 to reach it.

Answer 3

Since the elevators leave at the exact same time, begin time is 0 for both. It takes 45 secs for Elevator1 to reach the 9th floor and 1 min for Elevator2 to reach the ninth floor. Therefore, Elevator1 picks up the passengers and spends another 3 minutes on the 9th floor, meanwhile Elevator2 has already reached 8th floor and picks up the passengers there. When you see the relationship each elevator stops on alternate floor.
Total time taken by elevator1 = Time between floors + halt time
= 45 secs * 9 + (stop time on floor 9, 7, 5, 3) = 45secs * 9 + 3mins * 4 = 18 mins 45 secs.
Similarly for Elevator2 = 1min * 9 + (stop time on floor 8, 6, 4, 2) = 9 mins + 3 mins * 4 = 21 mins.

Therefore, Elevator1 reaches floor1 faster

Answer 4

If you assume that there are passengers to be picked up on floors 9 through 2 (and all exit on 1), then both elevators will make four stops, skipping the floor that the other occupies as it passes. In this case the faster elevator will reach the ground floor (1) before the other one. Again this assumes that they leave the tenth florr at the same time, and that the seond floor is the last with people to get on.

Answer 5

If you work this out floor by floor on paper, it takes 21 minutes for the slow one to come down, and 18:45 min for the fast one. They alternate floors picking up people so that doesn't make a difference. The fast one gets there first.

Answer 6

Dave is right.

The fastest elevator will make 3 stops on the 9th, 7th, 5th, and 3rd floors and reach the 1st floor in 1125 seconds

The slowest elevator will make stops on the 8th, 6th, 4th, and 2nd floors and come in a little over 2 minutes later at 1260 seconds.
.

Answer 7

the slower elevator because it says the first elevator to each floor has to stop that means the faster elevator will have to stop more times than the slower won so i say the slower elevator!!

Answer 8

The faster stop in the odd numbers.
The slower stop in the even numbers.
When one is stop the other go ahead.

So, the slower will stop in the 2 floor and the faster will go ahead, reaching the first floor.

Answer 9

the slower elevator, the fast one gets to stop at each floor, the slow one gets to keep movin' on

Answer 10

the fast one in 18:45