how would i do this problem? math.?

Question

[2(x – 1) + 3(x – 1)]
------------------------ (division line)
(x – 1)

Answer 1

[2(x-1) +3(x-1)] / (x-1)
= 2(x-1)/(x-1) + 3(x-1)/(x-1)
= 2+3
= 5
Assuming x does not equal 1 (because you cannot divide by zero).

Answer 2

Two ways depending on what you are looking for::

Read through both carefully:

The first method is division long handed:
............ _______________
.....x-1 | [2(x-1) + 3(x-1)

.................._____________
.............x-1| [2(x-1) + 3(x-1)
.......................x-1
......................-----------
........................2 +3(x-1)
........................-------------
.........................2 +3
----------------------5
answer is 5:

If you are solving for X you have to do it this way.

[2(x-1) + 3(x - 1)] / (x-1) = 0

muliply both sides by (x -1)

[2(x-1) + 3(x - 1)] = 0
clear paranthesis:

[2x - 2 + 3x - 3] = 0
combine terms and clear brackets.

5x - 5 = 0
take additive inverse of -5 on both sides of the equation:
(subtract both sides by a plus 5

5x - 5 +5 = 0 +5
combine terms: - 5 + 5 = 0. and 0 + 5 = 5

5x (+ or - ) 0 = 5

5x =5
now divde both sides by 5

5x/5 = 5/5 5x/5 will equal to x and 5/5 will equal to 1

x = 1
and if you plug 1 back into the eauation you will come out with the proof in one step which is:
0=0

This is an irrational equation where the only number the equation can equal to is 0 as further prove try another number: set the equation equal to. 2:
[2(x -1 ) + 3(x -1 )] /(x -1)=2
work it the same way as the proof:
multiply both sides by (x-1)
[2(x - 1) + 3(x - 1)] = 2( x-1)

now combine like terms on both sides of the equal and simplify: and clear the paranthesis and brackets.
[2x -2 + 3x -3] = 2x -2
combine like terms again.

2x + 3x - 2 - 3 = 2x -2

5x - 5 = 2x -2
use additive inverse next substract - 5 from both sides of the equaltion by changing signs and adding. You do this by adding +5 to both sides of the equation:

5x - 2x = 5 -2
3x = 3
x =1

Now check your answer:

[ [2(x - 1) + 3(x - 1)] / (x -1) ] = 2

[2(1 -1) + 3(1 - 1) ] / (1 - 1) =2
[2 -2 + 3 -3] / 0 =2
[0+0] / 0 = 2
0 =2 this is an irrational statement and every time the equation is solved it will come out to zero so this is an improper equation or false statement:

x will always come out to equal 1 which will make division by 0 necessary which proves out this is an incorrect statemeny and an inequality: anytime time x is greater than or less than zero: x<0 or x>0.

Never work building a bridge or designing an electrical circuit:

Answer 3

You divide both terms in the numerator (the "stuff" above the line) by x-1. That means all of the (x-1)s will cancel. You will be left with 2 + 3. So the answer is 5.

Answer 4

this would split into

[2(x-1)/(x-1)] + [3(x-1)/(x-1)]

2 + 3

5

Answer 5

[2(x – 1) + 3(x – 1)]
------------------------ (division line)
(x – 1)

2x - 2 + 3x - 3
-------------------
x - 1

5x - 5
---------
x - 1

5(x - 1)
----------
x - 1

= 5

Answer 6

What is it that you are attempting to do, what are you supposed to solve for?