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I had this question on a test. I got 360 what did you get?

2007-06-20 06:17:50 · 10 answers · asked by Choosing Life For Me ~ Experiencing A Break Over~ 2 in Science & Mathematics Mathematics

10 answers

360
[explanation_
90%=0.90
therefore, the required number is
324/0.90
=360 ]

2007-06-20 06:21:38 · answer #1 · answered by alpha 7 · 0 0

The easy way to do percents is to always use the proportion:

%/100 = part/whole

or

%/100 = "is"/"of"

So, in this problem you will plug in for % and "is":

90/100 = 324/x

Cross multiply and you get: 90x = 32400

Divide both sides by 90: x = 360

So 324 is 90% of 360.

I hope this helps!

2007-06-20 13:23:05 · answer #2 · answered by grad student 1 · 0 0

324/.9=360

2007-06-20 13:25:09 · answer #3 · answered by Dave B. 4 · 0 0

90% *x = 324
(90/100)x = 324
90x = 324 * 100
90x = 32400
9x = 3240
x = 3240/9
x = 360

2007-06-20 13:22:16 · answer #4 · answered by topsyk 3 · 0 0

here is an easy way to solve these problems, find what ten percent is....

90% is 324 so you can divide 324 by nine, you get 36.....36 is ten percent of the whole number so multiply it by ten

36 * 10 = 360

2007-06-20 13:47:28 · answer #5 · answered by swimmerchicksrule!!!1423 2 · 0 0

324 divided by 0.9 = 360 correct!
.

2007-06-20 13:20:39 · answer #6 · answered by tlbs101 7 · 0 0

Let x be the number.
90 % of x is 324.
324=90x/100
multiply both sides by 100

90x=32400
9x=3240
x=360

2007-06-20 13:27:54 · answer #7 · answered by cidyah 7 · 0 0

REMEMBER:

Is........%
---- = ------
of 100

so:

324......90
------ = ------ You can reduce, 90 and 100 w/ a 10 so ur left w/:
x.......... 100


324....... 9
------- = ------- You can reduce, 9 and 324 w/ a 3 so ur left w/:
x...........10

18......3
----- = ------ Reduce the 3 and the 18 with a 3 so ur left w/ :
x..........10

6..........1
----- = ------- Cross multiply 6 and 10 so ur left w/ x=60
x ........10

2007-06-20 16:25:34 · answer #8 · answered by curiosity2414 1 · 0 0

360 is correct!!!

2007-06-20 13:22:38 · answer #9 · answered by Anonymous · 0 0

How did u solve it?

2007-06-20 13:21:46 · answer #10 · answered by Suhena 4 · 0 1

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