a 500 kg cart rolling at 10 m/s or a 50 kg cart rolling at 100m/s?
An objects energy due to its relative postion
A) potential energy
B) kinetic energy
C)power
D) effiency
2007-06-20 05:57:28 · 5 answers · asked by Amy M 5 in Science & Mathematics ➔ Physics
1) KE = 0.5mv^2
0.5(500)(10^2) = 25,000 J
0.5(50)(100^2) = 250,000J
the second case.
2) A
2007-06-20 06:02:15 · answer #1 · answered by Math Stud 3 · 1⤊ 0⤋
Two Bodies Have Same Momentum.. That Means m1v1 =m2v2.. Let Us Assume m1 =1, v1 =2 & m2 =2 & v1=1( for assumption purposes only) For 1sr object KE = 1/2*1*2^2 =2 for second object... KE =1/2*2*1^2=1 ... It Is Clear That Object With Less Mass Will Have Higher Kinetic Energy... The Reason Behind This Is Velocity Is Raised To The Power 2 in Kinetic Energy Formula :) 100% Correct :) To All Those Fools Saying Heavier Has More KE... Just Go And Improve Your Stupid Knowledge
2016-05-20 22:25:21 · answer #2 · answered by jodi 3 · 0⤊ 0⤋
1.) The less massive cart has more kinetic energy, because it has a much higher velocity.
K.E. = ½ mv²
½ (500 kg)(10 m/s)² = ½ (50,000 kg m²/s²) = 25,000 J
½ (50 kg)(100 m/s)² = ½ (500,000 kg m²/s²) = 250,000 J
2.) A. Potential energy is defined as energy of relative position.
2007-06-20 06:19:30 · answer #3 · answered by MathBioMajor 7 · 1⤊ 0⤋
your mom rolling down a hill
2007-06-20 06:04:20 · answer #4 · answered by Andyroo 1 · 0⤊ 1⤋
50kg.
KE = 1/2mv^2
2007-06-20 06:06:22 · answer #5 · answered by lover of life 5 · 0⤊ 1⤋