This is a question on optics?

Question

consider that u r sitting in a room with any two adjacent sides and ceiling(top) as plane mirrors.then,
1. How many no of images are formed?
2. How many no of images can u ( person sitting in a room )can see?
3. How many images are erect and virtual?

Answer 1

take dis way
room=90
first 2 adjacent=90
1 adja + ceiling=90
2nd adja + ceiling=90



use mirror formular=360-1/n

where n=no of images;;;;;good luk
2 as many as formed
3all is virtual,erect=d no of images formed in d ceiling mirror

Answer 2

Assuming the 3 mirrors are planar and at right angles to each other, you have one image for each mirror, one for each pair of mirrors (2-mirror corner reflectors) and one more for the corner reflector formed by the 3 mirrors, for a total of seven. All images are virtual. In the 1-mirror reflections the axis perpendicular to the plane surface is reversed and the image is erect (ref. 1). In the 2-mirror corner reflector there is an additional reversal along the axis perpendicular to the line joining them. So a horizontal joint inverts the image relative to the vertical, and a vertical joint swaps left and right producing the image of yourself as others see you. In the 3-mirror reflections the corner reflector re-reverses both of the two perpendicular axes, forming an image that is left-right reversed and upside-down (ref. 2, page 170-3).

Answer 3

it may be a trick question too. so there are 4 images which can form( in my view point) 3 on the mirrors and 1 on the retina in our eye.
but we can only see 3 images on the mirrors which the observer can see.
all images are erect and virtual(plane mirrors always give erect and virtual images).
but there may be another aspect
no light source is mentioned so no images may form.
if the the person has mentioned a light source then all the above answers may apply.