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2square root 3 + square root 75+ 5 square root 27

3/x+2 = 5/x


square root x-4 +6=10


x^2-8x+6



x+1/16x * 4x^2/5x + 5

Please answer i have 15 min. no need to show work.

2007-06-20 03:18:43 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

2 √3 + √75 + 5 √27

2 √3 + √25 √3 + 5 √9 √3

2 √3 + 5 √3 + 5 x 3 √ 3

2 √3 + 5 √3 + 15 √3

2 + 5 + 15 √3

22 √3

- - - - - - - - s-

2007-06-20 04:30:47 · answer #1 · answered by SAMUEL D 7 · 1 0

2square root 3 + square root 75+ 5 square root 27
= 2√3 + √75 + 5√27
= 2√3 + √(25*3) + 5√(9*3)
= 2√3 + 5√3 + 15√3
= √3(2 + 5 + 15)
= 22√3





3/x+2 = 5/x
multiply both sides by x,
3 + 2x = 5
2x = 5 - 3 = 2
x = 2/2 = 1





square root x-4 +6=10
√x - 4 + 6 = 10
squaring both sides,
x - 16 + 36 = 100
x = 100 + 16 - 36 = 80





x^2-8x+6
I assume you mean: x² - 8x + 6
let x² - 8x + 6 = 0
factorise,
let a = 1, b = -8, c = 6

use the formula = [ -b +/- square root (b² - 4ac) ] / 2a

= [ -(-8) +/- square root (-8² - 4(1)(6) ] / 2(1)
= [ 8 +/- square root (64-24 ] / 2
= 8 +/- √40/2
= 4 +/- √40/2





x+1/16x * 4x^2/5x + 5
Sorry, I'm not able to decipher how the expression is like.
it could be:
[ x + (1/16)x ] * 4x² / (5x + 5)
or
[ x + (1/16)x ] * 4x^(2/5x + 5)

2007-06-20 10:37:15 · answer #2 · answered by jurassicko 4 · 1 0

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